Simplify \dfrac{1}{\sqrt2+sqrt3}+\dfrac{1}{\sqrt2-sqrt3}.
\( \dfrac{1}{\sqrt2+\sqrt 3}+\dfrac{1}{\sqrt 2-\sqrt 3}\\ =\dfrac{\sqrt 2-\sqrt 3+\sqrt 2+\sqrt 3}{2-3}\\ =\dfrac{2\sqrt{2}}{-1}\\ \color{blue}=-2\sqrt{2}\ or =-\sqrt{8}\)
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