At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a
bicycle path. The bicyclist heading north is riding 2 km/hour faster than the bicyclist heading south. At
11:30, they are 50 km apart. Find the two bicyclists’ rates.
+36915 Let x = slower cyclist then faster is x + 2
combined speed = 2x+2
in 2.5 hours they cover 50 km
rate * time = distance
(2x+2) (2.5) = 50 solve for x
5x + 5 = 50
5x = 45
x = 9 and the faster is 11 km/hr
