+2729 Will and Grace are canoeing on a lake. Will rows at $50$ meters per minute and Grace rows at $30$ meters per minute. Will starts rowing at $2$ p.m. from the west end of the lake, and Grace starts rowing from the east end of the lake at $2{:}45$ p.m. If they always row directly towards each other, and the lake is $2800$ meters across from the west side of the lake to the east side, at what time will the two meet?
+1950 First, let's calculate how far Will got before Grace even started to row,
We have d=st, where d is distance, s is speed, and t is time.
We have (45min)(50m/min)=2250m. Will rowed 2250m before Grace began.
Now, Will and Grace have to cover (2800m)–(2250m)=550m together.
We have
(50)(t)+(30)(t)=55080t=550t=550/80=6.875
6.875 minutes is about 6 minutes and 52 seconds.
The two started at 6:45, so they arrive at about 6:51:52 P.M. when they meet.
Thanks! :)
