Solve for x: (3x + 12)(x + 4) = (4x^2 + 8x + 8x^2)/(2x).
(3x+12)(x+4)=(
=3x2+12x+12x+12
= 3x2+24x+12
=x2+8x+4
2x * (3x + 12)(x + 4) = (4x^2 + 8x + 8x^2)
6x^3 + 48x^2 + 96x=12x^2 + 8x
6x^3 + 36x^2 + 88x=0
x [3x^2 + 18x + 44] = 0, solve for x
[3x^2 + 18x + 44] = 0 - use the quadratic formula to get:
x = 0 x = -3 - i sqrt(17/3) x = -3 + i sqrt(17/3)
