One integer is 5 less than another. The sum of their squares is 157. Find the integers.
Integers x and x-5
x^2 + ( x-5)^2 = 157
x^2 + x^2-10x+25 = 157
2x^2 -10x -132 =0 Quadratic FOrmula x = 11 and -6 so the other integer is 6 or -11
11 and 6 -6 and -11