+52 oh, haha I read the question wrong, just z^2 is much easier eh,
@Guest why bother asking forums when you could just use a calculator? 🤷‍♂️ Heres one https://web2.0calc.com/
+2668 We have \(j = 4\), \(a = 11\), and \(z = 16\), meaning \(jaz^2 = 4 \times 11 \times (16^2) = \color{brown}\boxed{11,264}\)
Note that the squared applies to the \(z\) only, not \(j \times a \times z\)
