+0

# Algebra

0
31
3

Suppose that j = 4, a = j + 7 and z = a + 5. What is the value of jaz^2?

Jul 27, 2022

#1
+45
-1

((4)(11)(16))^2

= 704*704

= 495616

Jul 27, 2022
#3
+45
0

oh, haha I read the question wrong, just z^2 is much easier eh,

@Guest why bother asking forums when you could just use a calculator? 🤷‍♂️ Heres one https://web2.0calc.com/

Limpeklimpe  Jul 28, 2022
#2
+2270
+3

We have $$j = 4$$$$a = 11$$, and $$z = 16$$, meaning $$jaz^2 = 4 \times 11 \times (16^2) = \color{brown}\boxed{11,264}$$

Note that the squared applies to the $$z$$ only, not $$j \times a \times z$$

Jul 27, 2022