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Suppose that j = 4, a = j + 7 and z = a + 5. What is the value of jaz^2?

 Jul 27, 2022
 #1
avatar+51 
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((4)(11)(16))^2 

= 704*704

= 495616

 Jul 27, 2022
 #3
avatar+51 
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oh, haha I read the question wrong, just z^2 is much easier eh,

@Guest why bother asking forums when you could just use a calculator? đź¤·â€Ťâ™‚️ Heres one https://web2.0calc.com/

Limpeklimpe  Jul 28, 2022
 #2
avatar+2666 
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We have \(j = 4\)\(a = 11\), and \(z = 16\), meaning \(jaz^2 = 4 \times 11 \times (16^2) = \color{brown}\boxed{11,264}\)

 

Note that the squared applies to the \(z\) only, not \(j \times a \times z\)

 Jul 27, 2022

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