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For what values of \(x\) is \(2x^2+8x\le-6\)? Express your answer in interval notation.

 Nov 24, 2020
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For what values of  x is \(2x^2+8x\leq -6\) ? Express your answer in interval notation.

 

Hello Guest!

 

\(2x^2+8x+6\le0\\ x^2+4x+3=0\)

         p        q

\(x=-\frac{p}{2}\pm \sqrt{(\frac{p}{2})^2-q}\\ x=-2\pm\sqrt{4-3}\)

\(x_1=-1\\ x_2=-3\)

 

\(For\ {\color{blue}-3\le x\le -1} \ is \ \color{blue}-2x^2+8x\leq -6. \)

laugh  !

 Nov 25, 2020
edited by asinus  Nov 25, 2020

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