For what values of \(x\) is \(2x^2+8x\le-6\)? Express your answer in interval notation.
+14905 For what values of x is \(2x^2+8x\leq -6\) ? Express your answer in interval notation.
Hello Guest!
\(2x^2+8x+6\le0\\ x^2+4x+3=0\)
p q
\(x=-\frac{p}{2}\pm \sqrt{(\frac{p}{2})^2-q}\\ x=-2\pm\sqrt{4-3}\)
\(x_1=-1\\ x_2=-3\)
\(For\ {\color{blue}-3\le x\le -1} \ is \ \color{blue}-2x^2+8x\leq -6. \)
!
