There exist constants a,h,k and such that 3x^2+72x+4=a(x-h)^2+k for all real numbers x Enter the ordered triple (a,h,k)
3x^2+72x+4=a(x-h)^2+k
3 (x^2 + 24x) + 4
3 (x+12)2 - (3)(144) + 4
3 (x+12)2 - 428
+36916 
