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There exist constants a,h,k and such that 3x^2+72x+4=a(x-h)^2+k
for all real numbers x Enter the ordered triple (a,h,k)

 Apr 3, 2022
 #1
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3x^2+72x+4=a(x-h)^2+k

3 (x^2 + 24x)      + 4

3 (x+12)2     -  (3)(144) + 4

3 (x+12)2 - 428  

 Apr 3, 2022

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