Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
+3
594
1
avatar+117 

log(2x)+logx2log4log(9a)Log(3a2)+log3+loga

 Sep 11, 2014

Best Answer 

 #1
avatar+118703 
+8

Is this the second time you posted this?

I'm sorry I did intend to look at it before.  

Can you mark the other one as done please when you get this answer.

 

log(2x)+logx2log4=log(2x×x2÷4)

and you can finish it.     

 

log(9a)Log(3a2)+log3+loga=log(9a×3a÷(3a2))

and you can finish it       

 Sep 11, 2014
 #1
avatar+118703 
+8
Best Answer

Is this the second time you posted this?

I'm sorry I did intend to look at it before.  

Can you mark the other one as done please when you get this answer.

 

log(2x)+logx2log4=log(2x×x2÷4)

and you can finish it.     

 

log(9a)Log(3a2)+log3+loga=log(9a×3a÷(3a2))

and you can finish it       

Melody Sep 11, 2014

2 Online Users

avatar