Find the largest value of x for which
x^2 + y^2 = 4x + 5y
has a solution, if x and y are real.
Notice that \(x^2 + y^2 = 4x + 5y\) is very similar to the equation of a circle.
We have \(x^2-4x+y^2-5y=0\).
Now, completing the square for both x and y, we get
\((x-2)^2+(y-5/2)^2=25/4+16\)
This is the official equation of a circle.
It has the center at \((2, 5/2)\) and a radius of \(\sqrt{89/4}\)
The largest value of x is basically the x value of the center added to the radius.
Thus, we have \(2+\frac{\sqrt{89}}{2} = \frac{4+\sqrt{89}}{2}\)
So our final answer is \(\frac{4+\sqrt{89}}{2}\)
Thanks! :)
Notice that \(x^2 + y^2 = 4x + 5y\) is very similar to the equation of a circle.
We have \(x^2-4x+y^2-5y=0\).
Now, completing the square for both x and y, we get
\((x-2)^2+(y-5/2)^2=25/4+16\)
This is the official equation of a circle.
It has the center at \((2, 5/2)\) and a radius of \(\sqrt{89/4}\)
The largest value of x is basically the x value of the center added to the radius.
Thus, we have \(2+\frac{\sqrt{89}}{2} = \frac{4+\sqrt{89}}{2}\)
So our final answer is \(\frac{4+\sqrt{89}}{2}\)
Thanks! :)