Algebra

First, let's put s in terms of t so we can do some subsitutions. We get

$s=-\frac{2\left(-4t+1\right)}{5}$ from the first equation. 

Subsituting this value of s into the second equation, we get

$3t-6\left(-\frac{2\left(-4t+1\right)}{5}\right)=9-2t$

Now, we solve for t. We get

$\frac{-23t+12}{5}=9\\-23t+12=45\\t=-\frac{33}{23}$

Now, we subsitute t back into the first equation to find s. We get

$s=-\frac{62}{23}$

We get 

$s=-\frac{62}{23},\:t=-\frac{33}{23}$

So our final answer is $(-62/23, -33/23)$

Thanks! :)