+1537 The quadratic equation $x^2-mx+24 = 10$ has roots $x_1$ and $x_2$. If $x_1$ and $x_2$ are integers, how many different values of $m$ are possible?
+1233
The quadratic equation $x^2-mx+24 = 10$ has roots $x_1$ and $x_2$. If $x_1$ and $x_2$ are integers, how many different values of $m$ are possible?
x^2-mx+24 = 10
Combine terms and put in
formatting as ax2 + bx + c x2 – mx + 14 = 0
The roots will be integers
that multiply to 14 The roots can be +1 & +14
–1 & –14
+2 & +7
or –2 & –7
So, m has four possible values, namely +15, –15, +9, or –9
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