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avatar+764 

The sequence $a_1$, $a_2$, $a_3,$ $\dots$ is defined by $a_1 = 1,$ $a_2 = 3,$ and
a_n = 2a_{n - 1} + a_{n - 2}.


Thus, the next few terms are $a_3 = 2a_2 + a_2 = 6 + 1 = 7$ and $a_4 = 2a_3 + a_2 = 14 + 3 = 17$.

 

Find the remainder when $a_8$ is divided by $3.$

 Jun 30, 2024
 #1
avatar+129739 
+1

a1 =  1

a2 = 3

a3 = 7

a4  = 17

a5 = 41

a6 = 99

a7  = 239

a8 = 577

 

577 mod 3  =  1

 

 

cool cool cool

 Jun 30, 2024

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