The quadratic 2x^2 - 3x + 29 has two imaginary roots. What is the sum of the squares of these roots? Express your answer as a decimal rounded to the nearest hundredth.
+36916 From Vieta
r1r2 =29/2
r1+r2 = - -3/2 = 3/2
( r1+r2)^2 = (3/2 )2 = r1^2 + r2^2 + 2r1r2
= 9/4 = r1^2 + r2^2 + 2(29/2)
r1^2 + r2^2 = 9/4 - 29 = -107/4
