would someone please factor this for me? its driving me insane!

here it is:

(x^8) -1

thanx!!

here it is:

(x^8) -1

thanx!!

PB&J sammiches
May 10, 2012

#1**0 **

(X^8)-1 =((x^4)^2)-1^2=[((x^2)^2) -1^2][(x^4)+1]

=[(x^2)-1^2][(x^2)+1][(x^4)+1]

=[x-1][x+1][(x^2)+1][(x^4)+1]

=[(x^2)-1^2][(x^2)+1][(x^4)+1]

=[x-1][x+1][(x^2)+1][(x^4)+1]

Guest May 10, 2012

#2**0 **

(x^8) -1

since 8 can be divide by two

8 / 2 = 4

definition of sum and difference

__a^2 - b^2 = (a - b)(a + b)__

we get,

**((x^4) - 1)((x^4) + 1)**

since 4 can be divide by two

4 / 2 = 2

**((x^4) + 1)((x^2) + 1)((x^2) - 1)**

since 2 can be divide by two

2 / 2 = 1

__((x^4) + 1)((x^2) + 1)(x - 1)(x + 1)__

since 8 can be divide by two

8 / 2 = 4

definition of sum and difference

we get,

since 4 can be divide by two

4 / 2 = 2

since 2 can be divide by two

2 / 2 = 1

Guest May 11, 2012