One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab^2 = 4. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)
ab4 = 48 (eq 1)
ab2 = 4 (eq 2)
solve (eq 2) for a a = 4 / b2
sub a back in to (eq 1) (4 / b2) • b4 = 48
(b4 / b2) = 48 / 4
b2 = 12
b = 2 • sqrt(3)
The problem doesn't ask for a
but sub b2 back in to (eq 2) a • 12 = 4
a = 4 / 12
a = 1 / 3
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+544 
