+118609
\(1/(1 + 1/(sqrt(3) + 2))\\ =\frac{1}{1 + \frac{1}{(\sqrt3 + 2)}}\\ =1\div( 1 + \frac{1}{(\sqrt3 + 2)})\\ =1\div( \frac{\sqrt3+2+1}{(\sqrt3 + 2)})\\ =1\div \frac{3+\sqrt3}{2+\sqrt3 }\\\)
Invert and multiply
then
multiply top and bottom by the conjugate of the bottom.
Can you take it from there?
