What are the zeros of the function?
f(x) = x^2 + x – 6
1, 6
–1, 6
–2, 3
2, –3
x^2 + x - 6 = 0 factor
(x + 3) ( x - 2) + 0
So
x + 3 = 0 or x - 2 = 0
x = - 3 x = 2