When the same constant is added to the numbers a, b, and c, a three-term geometric sequence arises. If a=60, b=100, and c=140, what is the common ratio of the resulting sequence?
Since the ratio between succesive terms is the same we have
[100 +n ] / [ 60 + n] = [ 140 + n ] / [ 100 + n ] cross- multiply
[100 + n ] [ 100 + n ] = [ 60 + n ] [140 + n]
10000 + 200n + n^2 = 8400 + 200n + n^2
10000 = 8400
No solutions exist
+750 
