If we know that b(b^4 * b^5)^2 = b^x for all real numbers b, what is the value of x?
b(b^4 * b^5)^2 = b^x
b(b^9)^2 = b^x
b*b^18 = b^x
b^19 = b^x
x = 19.
=^._.^=
