Find the value of $v$ such that $\frac{-21-\sqrt{201}}{10}$ a root of $5x^2+21x+v = 0$.
To find the asnwer we can plug in (-21-sqrt201)/100 as r
we square that number since we have to find x^2 to get (642+42sqrt201)/100 mutiply that 5 since that is the coeffcient to get (3210+210sqrt201)/100 and simplify to 32.1+2.1sqrt201
Then we do 21 times our number to get (-441-21sqrt201)/10 to get -44.1-2.1sqrt201
so we have
32.1+2.1sqrt201-44.1-2.1sqrt201+v=0
(32.1-44.1)+(2.1sqrt201-2.1sqrt201)+v=0 canceling gives us
-12+v=0
v=12
soorry for the misspelled words
To find the asnwer we can plug in (-21-sqrt201)/100 as r
we square that number since we have to find x^2 to get (642+42sqrt201)/100 mutiply that 5 since that is the coeffcient to get (3210+210sqrt201)/100 and simplify to 32.1+2.1sqrt201
Then we do 21 times our number to get (-441-21sqrt201)/10 to get -44.1-2.1sqrt201
so we have
32.1+2.1sqrt201-44.1-2.1sqrt201+v=0
(32.1-44.1)+(2.1sqrt201-2.1sqrt201)+v=0 canceling gives us
-12+v=0
v=12
soorry for the misspelled words