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Find the value of $v$ such that $\frac{-21-\sqrt{201}}{10}$ a root of $5x^2+21x+v = 0$.

 Jan 23, 2025

Best Answer 

 #1
avatar+28 
+1

To find the asnwer we can plug in (-21-sqrt201)/100 as r

we square that number since we have to find x^2 to get (642+42sqrt201)/100 mutiply that 5 since that is the coeffcient to get (3210+210sqrt201)/100 and simplify to 32.1+2.1sqrt201

Then we do 21 times our number to get (-441-21sqrt201)/10 to get -44.1-2.1sqrt201

so we have

32.1+2.1sqrt201-44.1-2.1sqrt201+v=0

(32.1-44.1)+(2.1sqrt201-2.1sqrt201)+v=0 canceling gives us

-12+v=0

v=12

soorry for the misspelled words

 Jan 24, 2025
 #1
avatar+28 
+1
Best Answer

To find the asnwer we can plug in (-21-sqrt201)/100 as r

we square that number since we have to find x^2 to get (642+42sqrt201)/100 mutiply that 5 since that is the coeffcient to get (3210+210sqrt201)/100 and simplify to 32.1+2.1sqrt201

Then we do 21 times our number to get (-441-21sqrt201)/10 to get -44.1-2.1sqrt201

so we have

32.1+2.1sqrt201-44.1-2.1sqrt201+v=0

(32.1-44.1)+(2.1sqrt201-2.1sqrt201)+v=0 canceling gives us

-12+v=0

v=12

soorry for the misspelled words

Iampanda Jan 24, 2025

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