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The parabolas defined by the equations y = x^2 + 4x + 6 and y = 1/2*x^2 + x + 4 intersect at (a,b) and (c,d) where c >= a. What is c - a?

 May 15, 2021
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*** edited ***   Equate the two parabolas and solve for x to find the x coordinates of where they intersect

 

x^2 + 4x + 6     =    1/2 x^2 + x + 4

1/2 x^2 + 3x + 2 = 0        use quadratic formula to find    x=−3 +- sqrt5   <===== this is a and c

    you should be able to finish this......    cheeky

 May 15, 2021
edited by ElectricPavlov  May 15, 2021
edited by ElectricPavlov  May 15, 2021

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