The parabolas defined by the equations y = x^2 + 4x + 6 and y = 1/2*x^2 + x + 4 intersect at (a,b) and (c,d) where c >= a. What is c - a?
+36916 *** edited *** Equate the two parabolas and solve for x to find the x coordinates of where they intersect
x^2 + 4x + 6 = 1/2 x^2 + x + 4
1/2 x^2 + 3x + 2 = 0 use quadratic formula to find x=−3 +- sqrt5 <===== this is a and c
you should be able to finish this...... 
