Find two consecutive positive integers such that the square of the smaller increased by 4 times thelarger is 64
x and x+1 are the numbers
x^2 + 4 (x+1) = 64
x^2 + 4x -60 = 0
(x+10)(x-6) = 0 x = -10 or 6 take 6 since we are looking for positive integers then x+1 = 7