Let a and b be real numbers such that a^3 + 3ab^2 = 679 and 3a^3 - ab^2 = 615. Find a - b.
\(a^3 + 3ab^2 = 679 ,3a^3 - ab^2 = 615\)
\(10a^3 = 3\cdot615+679\)
\(10a^3=2524\)
\(a = \sqrt[3]{252.4}\)
Uhh this doesn't look right. Maybe a moderator check? If it is, @Kittykat you can use this to find a-b, just plug in
+1341 
