Let a and b be real numbers such that a^3 + 3ab^2 = 679 and 3a^3 - ab^2 = 615. Find a - b.
a3+3ab2=679,3a3−ab2=615
10a3=3⋅615+679
10a3=2524
a=3√252.4
Uhh this doesn't look right. Maybe a moderator check? If it is, @Kittykat you can use this to find a-b, just plug in