Can anyone solve this?\((x+4)^2=x^2+(x+2)^2-2x^2*4x*\frac{-1}{2}\)
(x + 4)^2 = x^2 + (x + 2)^2 - 4x^3
x^2 + 8x + 16 = x^2 + x^2 + 4x + 4 - 4x^3
4x^3 - x^2 + 4x + 12 = 0
The Rational Zeroes Theorem won't help us here, so a graph seems to be the way to go
Only one real solution x ≈ -1.15
