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Can anyone solve this?
\((x+4)^2=x^2+(x+2)^2-2x^2*4x*\frac{-1}{2}\)

 Mar 8, 2024
 #1
avatar+129690 
+1

(x + 4)^2  = x^2 + (x + 2)^2 -  4x^3

 

x^2 + 8x + 16 =  x^2 + x^2 + 4x + 4  - 4x^3

 

4x^3  - x^2  + 4x + 12 = 0

 

The Rational Zeroes Theorem won't help us here, so a graph seems to be the way to go

 

 

Only one real solution  x ≈  -1.15

 

cool cool cool

 Mar 8, 2024

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