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Define a@b = ab - b^2 and a#b = a + b - ab. What is (6@2)/(6#2)?

 May 19, 2021
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algebra
Define
\(a@b = ab - b^2\) and
\(a\#b = a + b - ab\).
What is \((6@2)/(6\#2)\)?

 

\(\begin{array}{|rcll|} \hline (6@2)/(6\#2) &=& \dfrac{6@2}{6\#2)} \\\\ (6@2)/(6\#2) &=& \dfrac{6*2-2^2}{6+2-6*2} \\\\ (6@2)/(6\#2) &=& \dfrac{12-4}{8-12} \\\\ (6@2)/(6\#2) &=& \dfrac{8}{-4} \\\\ \mathbf{(6@2)/(6\#2)} &=& \mathbf{-2} \\ \hline \end{array}\)

 

laugh

 May 19, 2021

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