Give an example of a quadratic function that has zeroes at x=2 and x=-4, and that takes the value 6 when x=3.. Enter your answer in the expanded form "ax^2 + bx + c", where a,b,c are replaced by appropriate numbers.
If there are zeroes at x = 2 and x = -4, the quadratic must be in the form of a(x - 2)(x + 4)
Plugging in x = 3, a(3 - 2)(3 + 4) = 6, solve for a and expand the quadratic. :))