Find all real numbers \(x\) such that \( x^2 + \left\lfloor \frac x2 \right\rfloor + \left\lfloor \frac x3 \right\rfloor = 10. \)
Not sure how to solve this algebraically, but WolframAlpha gives a solution of -√14
Check
( -√14 )^2 + floor (-√14 / 2) + floor (-√14 / 3 ) =
14 + floor (≈ -1.87) + floor ( ≈ -1.247) =
14 - 2 - 2 =
10
