Algebra

$3^5(x+2)^3+3=27\\ 3^5(x+2)^3=24\\ (x+2)^3 = \dfrac{24}{3^5} = \dfrac{8}{81}\\ x+2 = \dfrac{2}{3\sqrt[3]{3}}\\ x = \dfrac{2}{3\sqrt[3]{3}} -2 = \\2\left( \dfrac{1}{3\sqrt[3]{3}} -1\right)$