Janine is 7 years younger than Lucy and 4 years older thanSamantha. The average of their ages is 16. What are their ages?
J = L-7
S = L-11
L
Averaged =16
(L-7 + L-11 + L) / 3 = 16
3L -18 = 48
3L = 66
L = 22 so J = 15 And S = 11
