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Solve for y if 9^y = 3^5*9/27.

 Jun 13, 2022
 #1
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I assume this is

 

9^y =  3^( 5*9 / 27)

 

(3^2)^y = 3^(45/27)

 

3^(2y)  = 3^(5/3)          solve for the exponents

 

2y =  5/3      multiply both sides by 1/2

 

y = (5/3)(1/2) =  5/6

 

 

cool cool cool

 Jun 13, 2022
edited by CPhill  Jun 13, 2022

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