Solve for y if 9^y = 3^5*9/27.
I assume this is
9^y = 3^( 5*9 / 27)
(3^2)^y = 3^(45/27)
3^(2y) = 3^(5/3) solve for the exponents
2y = 5/3 multiply both sides by 1/2
y = (5/3)(1/2) = 5/6
