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Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions:
2mn - 21m + 6n + mn - 9m + ___

 Mar 23, 2024

Best Answer 

 #1
avatar+394 
+1

\(3mn-30m+6n+c\)

\(3m(n - 10) + 6n + c\)

\(3m(n-10)+6(n-10)+60+c\)

\((3m+6)(n-10)+60+c\)

\(c+60 = 0\)

\(c=-60\)

The constant is -60.

 Mar 23, 2024
 #1
avatar+394 
+1
Best Answer

\(3mn-30m+6n+c\)

\(3m(n - 10) + 6n + c\)

\(3m(n-10)+6(n-10)+60+c\)

\((3m+6)(n-10)+60+c\)

\(c+60 = 0\)

\(c=-60\)

The constant is -60.

hairyberry Mar 23, 2024

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