+0  
 
0
31
1
avatar

Let f(x) = 1/(x + 2) for x > -2, and f(x) = 1/(x + 2) for x < -2. (f(x) is not defined at x = -2 .) Which integer is not in the range of f(x)?

 Jul 15, 2022
 #1
avatar+124525 
+1

We have a  low over high situation  in terms of  polynomials.....when this happens  there is a horizontal asymptote at y  = 0

 

So.....0  is not in the  range  of the  function

 

 

cool cool cool

 Jul 15, 2022

13 Online Users

avatar