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Completely simplify and rationalize the denominator:
\[\frac{\sqrt{160}}{\sqrt{252}}\times\frac{\sqrt{245}}{\sqrt{128}}\]

 Jan 15, 2022
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Completely simplify and rationalize the denominator.

 

Hello Guest!

 

\(\frac{\sqrt{160}}{\sqrt{252}}\times\frac{\sqrt{245}}{\sqrt{128}}\\ =\frac{\sqrt{2^5\cdot 5}}{\sqrt{2^2\cdot 3^2\cdot 7}}\times\frac{\sqrt{5\cdot 7^2}}{\sqrt{2^7}}\\ = \sqrt{\frac{2^5\cdot 5^2\cdot 7^2}{2^9\cdot 3^2\cdot 7}}\\ =\sqrt{\frac{5^2\cdot 7}{2^4\cdot 3^2}}\)

\(=\frac{5\cdot \sqrt{7}}{2^2\cdot 3} \)

laugh  !

 Jan 15, 2022

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