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Find the conic section represented by the equation

3x^2 + y^2 + 9x - 5y - 20 = 8x^2 + 6x + 47

 Feb 19, 2025
 #1
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3x^2 + y^2 + 9x - 5y - 20 = 8x^2 + 6x + 47

 

Simplify as

 

-5x^2 + 3x  + y^2 - 5y   =  67

 

y^2 - 5y  - 5x^2  + 3x  = 67

 

 

 

Hyperbola  

y^2  term positive

x^2 term  negative

 

cool cool cool

 Feb 20, 2025

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