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avatar+193 

Write the polynomial in factored form.

4x^3 + 8x^2 – 96x

 

6x(x + 4)(x – 4)

 

4x(x – 4)(x + 6)

 

4x(x + 6)(x + 4)

 

–4x(x + 6)(x + 4)

 Jan 29, 2019
 #1
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+1

Factor the following:
4 x^3 + 8 x^2 - 96 x

Factor 4 x out of 4 x^3 + 8 x^2 - 96 x:
4 x (x^2 + 2 x - 24)

The factors of -24 that sum to 2 are 6 and -4. So, x^2 + 2 x - 24 = (x + 6) (x - 4):

 4x (x + 6) (x - 4)

 Jan 29, 2019
 #2
avatar+7824 
+1

First, we see the g.c.d of the terms is 4x. We factor this out:

\(4x^3+8x^2-96x = 4x(x^2+2x-24)\).

Then we factor the quadratic. (If you don't know how, you can try expanding the expression in each option.)

\(4x^3+8x^2-96x = 4x(x^2+2x-24)=4x(x+6)(x-4)\).

 

So we see the answer is the second option.

 Feb 1, 2019

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