+129 Find the minimum value of 9^x - 2 \cdot 3^x + 1 over all real numbers x.
+2 Anything to the power of 0 is 1, so if x = 0, 9^x would be 1. Lets assume x = 0. Then \((9^x - 2) \cdot (3^x + 1)\) would be equal to \(-1 \cdot 1\) or -1. So, the minimum value of \((9^x - 2) \cdot (3^x + 1)\) is -1.
