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One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab^2 = 4. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)

 Jun 22, 2024
 #1
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ab^4 = 48

ab^2 = 4        divide the frist equation by the second

 

b^2 = 12

 

b = sqrt 12   = 2sqrt 3

 

cool cool cool

 Jun 22, 2024

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