One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab^2 = 4. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)
ab^4 = 48
ab^2 = 4 divide the frist equation by the second
b^2 = 12
b = sqrt 12 = 2sqrt 3
+1790 
