Algebra

Find C

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$p - 2q = 0\\ q - 2r = 0\\ p + r = 8$

$p=2q=8-r$

          $q=2r$

        $\underline{2q=4r}$

          $0=8-5r$

          $r=\frac{8}{5}$

$q=2r=2\cdot \frac{8}{5}$

$q=3\frac{1}{5}$

$p+r=8\\ p=8-r=8-\frac{5}{8}$

$p=7\frac{3}{8}$

$The\ ordered\ triple\ (p,q,r)\ is\ \color{blue}(7\frac{3}{8},3\frac{1}{5},1\frac{3}{5})$

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