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Find the unique pair of real numbers (x,y) satisfying
(3x^2 + 6x + 5)(2y^2 + 8y + 10) = 4.

 Feb 18, 2022
 #1
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(3x^2 + 6x + 5) is defined on the interval [2, infinity)

(2y^2 + 8y + 10) is defined on the interval [2, infinity)

Therefore, both 3x^2 + 6x + 5 = 2, and 2y^2 + 8y + 10 = 2.

Solve the equations and you have your answer :))

 

=^._.^=

 Feb 19, 2022

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