Find the unique pair of real numbers (x,y) satisfying (3x^2 + 6x + 5)(2y^2 + 8y + 10) = 4.
(3x^2 + 6x + 5) is defined on the interval [2, infinity)
(2y^2 + 8y + 10) is defined on the interval [2, infinity)
Therefore, both 3x^2 + 6x + 5 = 2, and 2y^2 + 8y + 10 = 2.
Solve the equations and you have your answer :))
=^._.^=
