Find the smallest value of x such that x^2 + 10x + 25 = 18.
First, move everything to the left side.
\(x^2+10x+7=0\)
use the binomial theorem to get \(x=-5+3√2, x=-5-3√2\)
The smaller answer is the second one, so that's the answer.
x^2 +10x+7 = 0 Use quadratic fromula a = 1 b = 10 c = 7
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) to find x = -5 +- 3sqrt 2 Pick the smaller one................
+15 
