Let

$$f(x) = \frac{1}{1+\frac{2}{1+\frac 3x}}.$$

There are three real numbers $x$ that are not in the domain of $f(x)$. What is the sum of those three numbers?

AUnVerifedTaxPayer Sep 28, 2024

#1**+1 **

*There are three real numbers x that are not in the domain of f(x).*

*What is the sum of those three numbers?*

**x = 0** results in a zero in the denominator 3 / x.

**x = –3** results in a zero in the denominator 2 / (1 + 3 / x).

**x = –1** results in a zero in the denominator 1 + 2 / (1+ 3 / x)

The sum of the three numbers is **– 4**.

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Bosco Oct 26, 2024