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The height (in meters) of a shot cannonball follows a trajectory given by h(t) = -4.9t^2 + 18t - 0.4 at time t (in seconds). As an improper fraction, for how long is the cannonball above a height of 6 meters?

 Nov 19, 2021
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Set h(t) = 6

6 = -4.9t^2 + 18t- .4

 0 = -4.9t^2 + 18t - 6.4     now use quadratic formula to solve for t.....

                                             you will get two 't' values ...the time above 6 m  will be the time between the two values

 Nov 19, 2021

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