+0  
 
-3
1
1
avatar+171 

Let x and y be nonnegative real numbers. If xy = \frac{2}{5}, then find the minimum value of 6x + \frac{3}{5y}.

 Jun 8, 2024
 #1
avatar+129399 
+1

xy = 2/5

y = (2/5)x^(-1)

 

6x +  3  / (5 * (2/5) x^(-1))  =  

 

6x +  (3/2)x  

 

(15/2) x

 

There is no minimum......this is a line through the origin with a slope of  15 / 2

 

cool cool cool

 Jun 8, 2024

3 Online Users

avatar