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Let x and y be nonnegative real numbers. If xy = \frac{2}{5}, then find the minimum value of 6x + \frac{3}{5y}.

 Jun 8, 2024
 #1
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xy = 2/5

y = (2/5)x^(-1)

 

6x +  3  / (5 * (2/5) x^(-1))  =  

 

6x +  (3/2)x  

 

(15/2) x

 

There is no minimum......this is a line through the origin with a slope of  15 / 2

 

cool cool cool

 Jun 8, 2024

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