(16x^8y^2)^1/2
sqrt(16x^8y^2)
4x^?y
~ what is the square root of x^8?
16x^8y^2)^1/2
since
\(x^4*x^4=x^8\\ \sqrt{x^8}=x^4\)
\(\sqrt{16x^8y^2}\\ =\sqrt{4*4*x^4*x^4*y*y}\\ =\sqrt{(4*x^4*y)\;\;\;*\;\;\;(4*x^4*y)}\\ =4*x^4*y\\ =4x^4y\)
