Rob purchased two house plants for a total of $58. If the grape ivy cost $12 more than the Boston fern, how much did the Boston fern cost?
+130517 Anonymous is correct......here's another approach.....
Let the cost of the Boston fern be x
Then, the grape ivy cost x + 12
And their combined cost is given by
x + ( x + 12) = 58 simplify
2x + 12 = 58 sbtract 12 from both sides
2x = 46 divide both sides by 2
x = $23 and that's the cost of the fern
$23 just find half which is 29 and take away 6 giving you the lower costing plant at $23
+130517 Anonymous is correct......here's another approach.....
Let the cost of the Boston fern be x
Then, the grape ivy cost x + 12
And their combined cost is given by
x + ( x + 12) = 58 simplify
2x + 12 = 58 sbtract 12 from both sides
2x = 46 divide both sides by 2
x = $23 and that's the cost of the fern
