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avatar+251 

Solve for x: \(\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)

 Dec 2, 2021
 #1
avatar+473 
+12

Use the Wolfram-Alpha Theorem to get x=-1/6

https://www.wolframalpha.com/input/?i=3%3D6x%2B4

edited by Guest  Dec 2, 2021
 #2
avatar+117437 
+3

\(\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\\ \frac{3(x+4)}{x+4} = \frac{12x^2 + 8x }{2x}\\ \frac{3(x+4)}{x+4} = \frac{4x(3x + 2 )}{2x}\\ 3= 2(3x + 2) \\ \frac{3}{2}= 3x + 2 \\ -\frac{1}{2}=3x\\ x=-\frac{1}{6}\)

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 Dec 2, 2021

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