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please help thanks

 May 11, 2019

Best Answer 

 #1
avatar+6046 
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\(3x+1 = 3(x-2) + 7\\ \dfrac{3x+1}{x-2}=\dfrac{3(x-2)+7}{x-2} = 3 + \dfrac{7}{x-2}\\ A=3\\ B=7\)

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 May 11, 2019
 #1
avatar+6046 
+1
Best Answer

\(3x+1 = 3(x-2) + 7\\ \dfrac{3x+1}{x-2}=\dfrac{3(x-2)+7}{x-2} = 3 + \dfrac{7}{x-2}\\ A=3\\ B=7\)

Rom May 11, 2019

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