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Find the value of k that makes the question an identity.

k(3x-2)=4-6x

Guest Mar 11, 2018
 #1
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0

No solution for k !!!

Guest Mar 11, 2018
 #2
avatar+12756 
+1

k=-2 is a solution

ElectricPavlov  Mar 11, 2018
 #3
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How did you solve for k = -2?

Guest Mar 11, 2018
edited by Guest  Mar 11, 2018
 #6
avatar+12756 
+1

3kx - 2k = 4 - 6x

 

3kx = -6x      and   -2k = 4

3k = -6          and     k = -2

  k = -2

ElectricPavlov  Mar 11, 2018
 #4
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+1

k(3x-2)=4-6x        divide both side by (3x - 2)

k =(4 - 6x) / (3x - 2)

k =-2(3x - 2) / (3x - 2)

k = -2

Guest Mar 11, 2018
edited by Guest  Mar 11, 2018
 #5
avatar+68 
+1

I'm gonna just do a different method if ya don't mind.

\(k(3x-2)=4-6x\)

\(k(3x-2)=-6x+4\)

\(k(3x-2)=-2(3x-2)\)

\(k = -2\)

CoopTheDupe  Mar 11, 2018

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