Algebraic Identities

Question

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1177

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Find the value of k that makes the question an identity.

k(3x-2)=4-6x

Guest Mar 11, 2018

Guest · Answer 1 · 2018-03-11T12:45:02

No solution for k !!!

ElectricPavlov · Answer 2 · 2018-03-11T01:24:20

k=-2 is a solution

Guest · Answer 3 · 2018-03-11T01:32:06

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How did you solve for k = -2?

Guest Mar 11, 2018

edited by Guest Mar 11, 2018

+37153

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3kx - 2k = 4 - 6x

3kx = -6x and -2k = 4

3k = -6 and k = -2

k = -2

Guest · Answer 4 · 2018-03-11T04:08:17

k(3x-2)=4-6x divide both side by (3x - 2)

k =(4 - 6x) / (3x - 2)

k =-2(3x - 2) / (3x - 2)

k = -2

CoopTheDupe · Answer 5 · 2018-03-11T07:04:58

I'm gonna just do a different method if ya don't mind.

\(k(3x-2)=4-6x\)

\(k(3x-2)=-6x+4\)

\(k(3x-2)=-2(3x-2)\)

\(k = -2\)