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\(\frac{27x^3-8y^3}{3x-2y}\)

Can this be divided using algebraic long division?

 

(27x- 8y3)/(3x-2y)

 

(if the latex doesn't load)

 Feb 27, 2017
edited by Guest  Feb 27, 2017
edited by Guest  Feb 27, 2017

Best Answer 

 #2
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+5

Right, so:

 

27x3 - 8y3 = (3x)3 - (2y)3

 

\(\frac{\left(3x-2y\right)\left(9x^2+6xy+4y^2\right)}{\left(3x-2y\right)}\)

= 9x+ 6xy + 4y2

 

Out of curiosity however, is it possible to use algebraic long division on something like this (with more than 1 variable?)

 

Thanks.

 Feb 27, 2017
 #1
avatar+118608 
0

(27x3 - 8y3)/(3x-2y)

 

You do not ned to use algebraioc long division.  Use this :))

 

\(\boxed{a^3-b^3=(a-b)(a^2+ab+b^2)}\)

 Feb 27, 2017
 #2
avatar
+5
Best Answer

Right, so:

 

27x3 - 8y3 = (3x)3 - (2y)3

 

\(\frac{\left(3x-2y\right)\left(9x^2+6xy+4y^2\right)}{\left(3x-2y\right)}\)

= 9x+ 6xy + 4y2

 

Out of curiosity however, is it possible to use algebraic long division on something like this (with more than 1 variable?)

 

Thanks.

Guest Feb 27, 2017
 #3
avatar+118608 
0

Hi Guest,

You are lucky that I saw this continued question.  It would be a good idea for you to become a member because then you would be able to send me a private message with a link to this thread and ask me to come back to it again.

PLUS I could be much more sure that you see any late answer that may be added.  :)

 

Yes you can do algebraic division with more than one variable, I have seen other mathematicians use it and I can use it on this one but I am not sure how often it is useful....

 

Doing Algebraic division with LaTex is difficult.

I have done it before with great sucess but it was extremely time consuming. ://

I'll give it a go.

This is different from how I did it before, This is quicker but not quite as nice.

 

\(\begin{array}{llllll}\\ &&9x^2&\color{Maroon}{+4y^2}&\color{NavyBlue}{+6xy}&&\\\hline 3x-2y|&&27x^3&-8y^3\\ &&27x^3&&-18yx^2\\\hline &&&-8y^3&\color{NavyBlue}{+18yx^2}\\ &&&&+18yx^2&-12xy^2\\\hline &&&-8y^3&&\color{Maroon}{+12xy^2}\\ &&&-8y^3&&+12xy^2\\\hline &&&+0&&+0\\\hline \end{array}\)

 

 

Heureka or maybe Max

Could you please show me how to make the horizontal lines the correct length ??  

 Feb 27, 2017
 #4
avatar+26367 
+5

hi Melody,

typesetting polynom division can easy be done with the polynom package:

see: http://tex.stackexchange.com/questions/79182/how-to-draw-polynom-division

 

Example: \((27x^3 - 8y^3)/(3x-2y)\)

\usepackage{polynom}

 

\begin{document}

  

   \textbf{Style A:}\par % this is the default
   \polylongdiv[style=A]{27x^3 - 8y^3}{3x-2y}

  

   \textbf{Style B:}\par
   \polylongdiv[style=B]{27x^3 - 8y^3}{3x-2y}

  

   \textbf{Style C:}\par
   \polylongdiv[style=C]{27x^3 - 8y^3}{3x-2y}

 

\end{document}

 

 

laugh

heureka  Feb 28, 2017
 #5
avatar+118608 
0

 

 

Thanks very much Heureka,

 

But

This does not work in this forum though does it?  I cannot make it work :/ I asume the polynom package is not included. :(

 

Do you do it all directly on your hard drive or do you go to somewhere else on the net to do LaTex like this ?

Melody  Feb 28, 2017
 #6
avatar+26367 
0

Hi Melody,

 

i have installed Latex on my Computer. The setup include a TexStudio.

See picture:

all free-software.

 

Then i have snapped it as image into web2.0calc.

I do it all directly on my hard drive.

 

Here i think we have a minimal latex.

 

laugh

heureka  Feb 28, 2017
 #7
avatar+26367 
0

 

see: https://miktex.org/download

 

...Download and run the Basic MiKTeX installer to setup a basic TeX/LaTeX system on your computer. Please read the tutorial, if you want step-by-step guidance...

 

laugh

heureka  Feb 28, 2017

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